H=-49t^2+43t

Solution for H=-49t^2+43t equation:

=-49H^2+43H

We move all terms to the left:

-(-49H^2+43H)=0

We get rid of parentheses

49H^2-43H=0

a = 49; b = -43; c = 0;
Δ = b2-4ac
Δ = -432-4·49·0
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-43}{2*49}=\frac{0}{98}
=0
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+43}{2*49}=\frac{86}{98}
=43/49
$